试说明无论x取何值,代数式5(x²+2)-(3x²+4)-2x²的值与x无关
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/27 15:23:16
![试说明无论x取何值,代数式5(x²+2)-(3x²+4)-2x²的值与x无关](/uploads/image/z/5907815-71-5.jpg?t=%E8%AF%95%E8%AF%B4%E6%98%8E%E6%97%A0%E8%AE%BAx%E5%8F%96%E4%BD%95%E5%80%BC%2C%E4%BB%A3%E6%95%B0%E5%BC%8F5%EF%BC%88x%26%23178%3B%2B2%EF%BC%89-%EF%BC%883x%26%23178%3B%2B4%EF%BC%89-2x%26%23178%3B%E7%9A%84%E5%80%BC%E4%B8%8Ex%E6%97%A0%E5%85%B3)
试说明无论x取何值,代数式5(x²+2)-(3x²+4)-2x²的值与x无关
试说明无论x取何值,代数式5(x²+2)-(3x²+4)-2x²的值与x无关
试说明无论x取何值,代数式5(x²+2)-(3x²+4)-2x²的值与x无关
5(x²+2)-(3x²+4)-2x²
=5x²+10-3x²-4-2x²
=6
化简后不含x
∴无论x取何值,代数式5(x²+2)-(3x²+4)-2x²的值与x无关
5(x²+2)-(3x²+4)-2x²=5x²+10-3x²-4-2x²=(5-3-2)x²+10-4=6,所以代数式5(x²+2)-(3x²+4)-2x²的值与x无关
展开5x2+10-3x2-4-2x2=6