=1/2*(sin2x-cos2x)-1/2是怎么变成 =√2/2*sin(2x+π/4)-1/2
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![=1/2*(sin2x-cos2x)-1/2是怎么变成 =√2/2*sin(2x+π/4)-1/2](/uploads/image/z/5905089-9-9.jpg?t=%3D1%2F2%2A%28sin2x-cos2x%29-1%2F2%E6%98%AF%E6%80%8E%E4%B9%88%E5%8F%98%E6%88%90+%3D%E2%88%9A2%2F2%2Asin%282x%2B%CF%80%2F4%29-1%2F2)
=1/2*(sin2x-cos2x)-1/2是怎么变成 =√2/2*sin(2x+π/4)-1/2
=1/2*(sin2x-cos2x)-1/2是怎么变成 =√2/2*sin(2x+π/4)-1/2
=1/2*(sin2x-cos2x)-1/2是怎么变成 =√2/2*sin(2x+π/4)-1/2
1/2*(sin2x-cos2x)-1/2 括号内提取√2
=√2/2*(√2/2xin2x-√2/2cos2x)-1/2
=√2/2*(sin2xcosπ/4-cos2xsinπ/4)-1/2
=√2/2*sin(2x-π/4)-1/2
你的题中是=√2/2*sin(2x+π/4)-1/2错了.