2f(x)+x^2f(1/x)=(3x³-x²+4x+3)/(x+1) 2x²f(1/x)+f(x)=(3-x+4x²+3x³)/(x+1)这两步是怎么简化来的,
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 23:03:16
![2f(x)+x^2f(1/x)=(3x³-x²+4x+3)/(x+1) 2x²f(1/x)+f(x)=(3-x+4x²+3x³)/(x+1)这两步是怎么简化来的,](/uploads/image/z/5904266-50-6.jpg?t=2f%28x%29%2Bx%5E2f%281%2Fx%29%3D%283x%26%23179%3B-x%26%23178%3B%2B4x%2B3%29%2F%28x%2B1%29+2x%26%23178%3Bf%281%2Fx%29%2Bf%28x%29%3D%283-x%2B4x%26%23178%3B%2B3x%26%23179%3B%29%2F%28x%2B1%29%E8%BF%99%E4%B8%A4%E6%AD%A5%E6%98%AF%E6%80%8E%E4%B9%88%E7%AE%80%E5%8C%96%E6%9D%A5%E7%9A%84%2C)
2f(x)+x^2f(1/x)=(3x³-x²+4x+3)/(x+1) 2x²f(1/x)+f(x)=(3-x+4x²+3x³)/(x+1)这两步是怎么简化来的,
2f(x)+x^2f(1/x)=(3x³-x²+4x+3)/(x+1) 2x²f(1/x)+f(x)=(3-x+4x²+3x³)/(x+1)
这两步是怎么简化来的,
2f(x)+x^2f(1/x)=(3x³-x²+4x+3)/(x+1) 2x²f(1/x)+f(x)=(3-x+4x²+3x³)/(x+1)这两步是怎么简化来的,
令x=1/t,有
2f(1/t)+(1/t)^2f(t)=...
化简去分母后
2t²f(1/t)+f(t)=(3-t+4t²+3t³)/(t+1)
用1/x替换上式子中的x 2f(1/x) f(x) /x^2 = (3/x^3 - 1/x^2 4/x 3)*x/(x 1) = (3 - x 4x^2 3x^3)/[(x
已知f(x)满足2f(x)+f(1/x)=3x,求f(x)
F(X)满足F(x)+2f(x分之1)=3X,求f(x)
已知f(x)满足2f(x)+f(1/x)=3x,求f(x)?
已知f(x)满足2f(x)+f(-x)=-3x+1,求f(x)
已知f(x)满足f(x)+2f(1/x)=3x,求f(x) ,
已知函数f(x)=x^3+x^2-2x-x,f(1)f(2)
f(x)满足f(-x)+2f(x)=x+3,则f(1)等于
已知f(x)+2f(1/x)=x+2/x+3,求f(x)
设f(x)={3x-1,x=0,求f(-x),f(x-2).
f(x+1)+f(x-1)=4x^3-2x求f(x)
已知f(x+1/x-1)=3f(x)-2x,求f(x)
f(1+x)+2f(1-x)=3x^2 求f(x)f(1+x)+2f(1-x)=3x^2求f(x)
f(x)+2f(1/x)=3x
f(x+2)>=f(x)+2,f(x+3)
f(x)=5x+3 f(x)=5x f(x)=x+2x+1 f(x)=5x+3 f(x)=5x f(x)=x+2x+1
f(X)=f(X+2)(x
F(x)=3x^2+2x-1 求F(x+△x)-f(x)/ △x
若f(x)满足f(x)-2f(1/x)=x,则f(x)=?