已知x²+4y平方-2x=4y-2,求(2x-3y)²-(3y-x)²的值
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已知x²+4y平方-2x=4y-2,求(2x-3y)²-(3y-x)²的值
已知x²+4y平方-2x=4y-2,求(2x-3y)²-(3y-x)²的值
已知x²+4y平方-2x=4y-2,求(2x-3y)²-(3y-x)²的值
已知x²+4y平方-2x=4y-2
x^2-2x+1+4y^2-4y+1=0
(x-1)^2+(2y-1)^2=0
x=1,y=1\2
(2x-3y)²-(3y-x)²
=(2-3\2)^2-(3\2-1)^2
=0
x²+4y平方-2x=4y-2
x^2+4y^2-2x-4y+2=0
(x-1)^2+(2y-1)^2=0
x-1=0
2y-1=0
x=1
y=1/2
(2x-3y)²-(3y-x)²
=(2x-3y-3y+x)(2x-3y+3y-x)
=-6y*x
=-6xy
=-6*1*1/2
=-3