ab=-2 a+b=3 求ab(a²+b²)-a-b
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ab=-2 a+b=3 求ab(a²+b²)-a-b
ab=-2 a+b=3 求ab(a²+b²)-a-b
ab=-2 a+b=3 求ab(a²+b²)-a-b
a^2+b^2=(a+b)^2-2ab=9+4=13
原式=(-2)*13-3=-26-3=-29
ab(a^2+b^2-a-b
=ab[(a+b)^2-2ab]-(a+b)
=-2(9+4)+2
=-26+2
=24