已知cos[a-(b/2)]=-1/9,sin(a/2-b)=2/3,且π/2<a<π,0<b<π/2,求cos(a+b)的值
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![已知cos[a-(b/2)]=-1/9,sin(a/2-b)=2/3,且π/2<a<π,0<b<π/2,求cos(a+b)的值](/uploads/image/z/5503576-40-6.jpg?t=%E5%B7%B2%E7%9F%A5cos%5Ba-%28b%2F2%29%5D%3D-1%2F9%2Csin%28a%2F2-b%29%3D2%2F3%2C%E4%B8%94%CF%80%2F2%EF%BC%9Ca%EF%BC%9C%CF%80%2C0%EF%BC%9Cb%EF%BC%9C%CF%80%2F2%2C%E6%B1%82cos%EF%BC%88a%2Bb%EF%BC%89%E7%9A%84%E5%80%BC)
已知cos[a-(b/2)]=-1/9,sin(a/2-b)=2/3,且π/2<a<π,0<b<π/2,求cos(a+b)的值
已知cos[a-(b/2)]=-1/9,sin(a/2-b)=2/3,且π/2<a<π,0<b<π/2,求cos(a+b)的值
已知cos[a-(b/2)]=-1/9,sin(a/2-b)=2/3,且π/2<a<π,0<b<π/2,求cos(a+b)的值
http://zhidao.baidu.com/question/168604222.html
算法一样,只是数值有点差别