C++编程题 关于矩阵...2470.Matrix Commutative Multiplication限制条件时间限制:5 秒,内存限制:256 兆 Given a square matrix of order N.Your task is to check whether AB=BA for all square matrix of the same order N.输入格式The input
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![C++编程题 关于矩阵...2470.Matrix Commutative Multiplication限制条件时间限制:5 秒,内存限制:256 兆 Given a square matrix of order N.Your task is to check whether AB=BA for all square matrix of the same order N.输入格式The input](/uploads/image/z/5492616-24-6.jpg?t=C%2B%2B%E7%BC%96%E7%A8%8B%E9%A2%98+%E5%85%B3%E4%BA%8E%E7%9F%A9%E9%98%B5...2470.Matrix+Commutative+Multiplication%E9%99%90%E5%88%B6%E6%9D%A1%E4%BB%B6%E6%97%B6%E9%97%B4%E9%99%90%E5%88%B6%3A5+%E7%A7%92%2C%E5%86%85%E5%AD%98%E9%99%90%E5%88%B6%3A256+%E5%85%86+Given+a+square+matrix+of+order+N.Your+task+is+to+check+whether+AB%3DBA+for+all+square+matrix+of+the+same+order+N.%E8%BE%93%E5%85%A5%E6%A0%BC%E5%BC%8FThe+input)
C++编程题 关于矩阵...2470.Matrix Commutative Multiplication限制条件时间限制:5 秒,内存限制:256 兆 Given a square matrix of order N.Your task is to check whether AB=BA for all square matrix of the same order N.输入格式The input
C++编程题 关于矩阵...
2470.Matrix Commutative Multiplication
限制条件
时间限制:5 秒,内存限制:256 兆
Given a square matrix of order N.Your task is to check whether AB=BA for all square matrix of the same order N.
输入格式The input begins with the integer t,the number of test cases.Then t test cases follow.
For each test case:In the first line there is an integer N (N
C++编程题 关于矩阵...2470.Matrix Commutative Multiplication限制条件时间限制:5 秒,内存限制:256 兆 Given a square matrix of order N.Your task is to check whether AB=BA for all square matrix of the same order N.输入格式The input
给定一个N阶方阵A,你的任务就是检验对所有的N阶方阵B,AB==BA是否成立.
输入格式为:第一行为测试例子的个数t,接着是t个测试例子.
对每一个测试例子,第一行是N就是方阵的阶数,在接下来的N行中,每行有N个整数.所有的整数都不超过1000(就是输入方阵的数据).
输出格式是:如果给定的N阶方阵A,对所有的N阶方阵B,AB==BA成立,输出“YES”,否则输出“NO”.
(题中给出的数据第二个方阵是单位阵,所以成立,就输出“YES”)
(以上是题意,怎么做等人来回答吧)