设A={(x,y)丨2x+y=1},B={(x,y)丨x-2y=2},求A交B
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![设A={(x,y)丨2x+y=1},B={(x,y)丨x-2y=2},求A交B](/uploads/image/z/5467636-28-6.jpg?t=%E8%AE%BEA%3D%EF%BD%9B%EF%BC%88x%2Cy%EF%BC%89%E4%B8%A82x%2By%3D1%EF%BD%9D%2CB%3D%7B%28x%2Cy%29%E4%B8%A8x-2y%3D2%7D%2C%E6%B1%82A%E4%BA%A4B)
设A={(x,y)丨2x+y=1},B={(x,y)丨x-2y=2},求A交B
设A={(x,y)丨2x+y=1},B={(x,y)丨x-2y=2},求A交B
设A={(x,y)丨2x+y=1},B={(x,y)丨x-2y=2},求A交B
把2x+y=1与x-2y=2看做两条直线,求A交B,也就是求两条直线的点集的较急,即,A交B为(4/5,-3/5)不懂再问.