怎样使5x [] 2x [] x [] 3 [] 4x =6x/3等式成立?[]中填入分别+,-,*,/,且每个符号只能用一次.
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 12:08:15
![怎样使5x [] 2x [] x [] 3 [] 4x =6x/3等式成立?[]中填入分别+,-,*,/,且每个符号只能用一次.](/uploads/image/z/5442774-6-4.jpg?t=%E6%80%8E%E6%A0%B7%E4%BD%BF5x+%5B%5D+2x+%5B%5D+x+%5B%5D+3+%5B%5D+4x+%3D6x%2F3%E7%AD%89%E5%BC%8F%E6%88%90%E7%AB%8B%3F%5B%5D%E4%B8%AD%E5%A1%AB%E5%85%A5%E5%88%86%E5%88%AB%2B%2C-%2C%2A%2C%2F%2C%E4%B8%94%E6%AF%8F%E4%B8%AA%E7%AC%A6%E5%8F%B7%E5%8F%AA%E8%83%BD%E7%94%A8%E4%B8%80%E6%AC%A1.)
怎样使5x [] 2x [] x [] 3 [] 4x =6x/3等式成立?[]中填入分别+,-,*,/,且每个符号只能用一次.
怎样使5x [] 2x [] x [] 3 [] 4x =6x/3等式成立?
[]中填入分别+,-,*,/,且每个符号只能用一次.
怎样使5x [] 2x [] x [] 3 [] 4x =6x/3等式成立?[]中填入分别+,-,*,/,且每个符号只能用一次.
再清楚点啊,看不懂
6x/3=2x???
题目中可以加括号么
如果不可以应该没有答案,一共24种填法我都试了
???
Good Luck!!!
让x=0
-一共就16种情况,自己算算就知道了。
5x + 2x - x * 3 / 4x = ?
5x + 2x - x / 3 * 4x = ?
5x + 2x * x - 3 / 4x = ?
5x + 2x * x / 3 - 4x = ?
5x - 2x + x * 3 / 4x = ?
5x - 2x + x / 3 * 4x = ?
5...
全部展开
-一共就16种情况,自己算算就知道了。
5x + 2x - x * 3 / 4x = ?
5x + 2x - x / 3 * 4x = ?
5x + 2x * x - 3 / 4x = ?
5x + 2x * x / 3 - 4x = ?
5x - 2x + x * 3 / 4x = ?
5x - 2x + x / 3 * 4x = ?
5x - 2x * x + 3 / 4x = ?
5x - 2x * x / 3 + 4x = ?
5x * 2x + x - 3 / 4x = ?
5x * 2x + x / 3 - 4x = 6x+x/3
5x * 2x - x + 3 / 4x = ?
5x * 2x - x / 3 + 4x = ?
5x / 2x + x - 3 * 4x = ?
5x / 2x + x * 3 - 4x = ?
5x / 2x - x + 3 * 4x = ?
5x / 2x - x * 3 + 4x = ?
收起