xy=m,且1/x2+1/y2=n,则(x-y)2=3y=x+2z,那么x2+9y2+4z2-6xy-12yz+4xz=
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![xy=m,且1/x2+1/y2=n,则(x-y)2=3y=x+2z,那么x2+9y2+4z2-6xy-12yz+4xz=](/uploads/image/z/5411640-48-0.jpg?t=xy%3Dm%2C%E4%B8%941%2Fx2%2B1%2Fy2%3Dn%2C%E5%88%99%EF%BC%88x-y%292%3D3y%3Dx%2B2z%2C%E9%82%A3%E4%B9%88x2%2B9y2%2B4z2-6xy-12yz%2B4xz%3D)
xy=m,且1/x2+1/y2=n,则(x-y)2=3y=x+2z,那么x2+9y2+4z2-6xy-12yz+4xz=
xy=m,且1/x2+1/y2=n,则(x-y)2=
3y=x+2z,那么x2+9y2+4z2-6xy-12yz+4xz=
xy=m,且1/x2+1/y2=n,则(x-y)2=3y=x+2z,那么x2+9y2+4z2-6xy-12yz+4xz=
(x^2+y^2)/(xy)^2=n
x^2+y^2=m^2n
(x-y)^2=m^2n-2m