[(1+tanx)cos^2x]/[cos2x+sin2x]=1/2+1/[2sqrt(2)sin(2x+π/4)]怎么推导出来的?
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![[(1+tanx)cos^2x]/[cos2x+sin2x]=1/2+1/[2sqrt(2)sin(2x+π/4)]怎么推导出来的?](/uploads/image/z/5263198-70-8.jpg?t=%5B%281%2Btanx%29cos%5E2x%5D%2F%5Bcos2x%2Bsin2x%5D%3D1%2F2%2B1%2F%5B2sqrt%282%29sin%282x%2B%CF%80%2F4%29%5D%E6%80%8E%E4%B9%88%E6%8E%A8%E5%AF%BC%E5%87%BA%E6%9D%A5%E7%9A%84%3F)
[(1+tanx)cos^2x]/[cos2x+sin2x]=1/2+1/[2sqrt(2)sin(2x+π/4)]怎么推导出来的?
[(1+tanx)cos^2x]/[cos2x+sin2x]=1/2+1/[2sqrt(2)sin(2x+π/4)]
怎么推导出来的?
[(1+tanx)cos^2x]/[cos2x+sin2x]=1/2+1/[2sqrt(2)sin(2x+π/4)]怎么推导出来的?
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