若集合A={x|log(1/2)x≥1/2},则CRA=(1/2)是底数A,(-无穷大,0】∪(√2/2,+无穷大)B,(√2/2,+无穷大)C,(-无穷大,0∪【√2/2,+无穷大)D,【√2/2,+无穷大)
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![若集合A={x|log(1/2)x≥1/2},则CRA=(1/2)是底数A,(-无穷大,0】∪(√2/2,+无穷大)B,(√2/2,+无穷大)C,(-无穷大,0∪【√2/2,+无穷大)D,【√2/2,+无穷大)](/uploads/image/z/5256860-68-0.jpg?t=%E8%8B%A5%E9%9B%86%E5%90%88A%3D%EF%BD%9Bx%7Clog%281%2F2%29x%E2%89%A51%2F2%EF%BD%9D%2C%E5%88%99CRA%3D%EF%BC%881%2F2%EF%BC%89%E6%98%AF%E5%BA%95%E6%95%B0A%2C%EF%BC%88-%E6%97%A0%E7%A9%B7%E5%A4%A7%2C0%E3%80%91%E2%88%AA%EF%BC%88%E2%88%9A2%2F2%2C%2B%E6%97%A0%E7%A9%B7%E5%A4%A7%EF%BC%89B%2C%EF%BC%88%E2%88%9A2%2F2%2C%2B%E6%97%A0%E7%A9%B7%E5%A4%A7%EF%BC%89C%2C%EF%BC%88-%E6%97%A0%E7%A9%B7%E5%A4%A7%2C0%E2%88%AA%E3%80%90%E2%88%9A2%2F2%2C%2B%E6%97%A0%E7%A9%B7%E5%A4%A7%EF%BC%89D%2C%E3%80%90%E2%88%9A2%2F2%2C%2B%E6%97%A0%E7%A9%B7%E5%A4%A7%EF%BC%89)
若集合A={x|log(1/2)x≥1/2},则CRA=(1/2)是底数A,(-无穷大,0】∪(√2/2,+无穷大)B,(√2/2,+无穷大)C,(-无穷大,0∪【√2/2,+无穷大)D,【√2/2,+无穷大)
若集合A={x|log(1/2)x≥1/2},则CRA=
(1/2)是底数
A,(-无穷大,0】∪(√2/2,+无穷大)B,(√2/2,+无穷大)C,(-无穷大,0∪【√2/2,+无穷大)D,【√2/2,+无穷大)
若集合A={x|log(1/2)x≥1/2},则CRA=(1/2)是底数A,(-无穷大,0】∪(√2/2,+无穷大)B,(√2/2,+无穷大)C,(-无穷大,0∪【√2/2,+无穷大)D,【√2/2,+无穷大)
log(1/2)x≥1/2解得0
AC一样。
选A