若方程x^2+2(1+a)x+3a^2+4ab+4b^2+2=0有实根,则b/a=
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![若方程x^2+2(1+a)x+3a^2+4ab+4b^2+2=0有实根,则b/a=](/uploads/image/z/5256488-56-8.jpg?t=%E8%8B%A5%E6%96%B9%E7%A8%8Bx%5E2%2B2%281%2Ba%29x%2B3a%5E2%2B4ab%2B4b%5E2%2B2%3D0%E6%9C%89%E5%AE%9E%E6%A0%B9%2C%E5%88%99b%2Fa%3D)
若方程x^2+2(1+a)x+3a^2+4ab+4b^2+2=0有实根,则b/a=
若方程x^2+2(1+a)x+3a^2+4ab+4b^2+2=0有实根,则b/a=
若方程x^2+2(1+a)x+3a^2+4ab+4b^2+2=0有实根,则b/a=
x^2+2(1+a)x+3a^2+4ab+4b^2+2=0
x^2+2(a+1)x+(a+1)^2+(4ab+4b^2+1+2a^2-2a)=0
则4ab+4b^2+1+2a^2-2a