已知x,y满足x²+4y²+2x-4y+2=0,则√5x²+16y²=
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![已知x,y满足x²+4y²+2x-4y+2=0,则√5x²+16y²=](/uploads/image/z/5255133-69-3.jpg?t=%E5%B7%B2%E7%9F%A5x%2Cy%E6%BB%A1%E8%B6%B3x%26%23178%3B%2B4y%26%23178%3B%2B2x-4y%2B2%3D0%2C%E5%88%99%E2%88%9A5x%26%23178%3B%2B16y%26%23178%3B%EF%BC%9D)
已知x,y满足x²+4y²+2x-4y+2=0,则√5x²+16y²=
已知x,y满足x²+4y²+2x-4y+2=0,则√5x²+16y²=
已知x,y满足x²+4y²+2x-4y+2=0,则√5x²+16y²=
x^2+2x+1+4y^2--4y+1=0
(x+1)^2+(2y--1)^2=0
x=--1,y=1/2
所以 根号(5x^2+16y^2)=根号(5+4)
=根号9
=3.