已知a²-2ab=5,b²+3ab=6,则a²+ab+b²=(),a²-5ab-b²=()
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![已知a²-2ab=5,b²+3ab=6,则a²+ab+b²=(),a²-5ab-b²=()](/uploads/image/z/4521535-7-5.jpg?t=%E5%B7%B2%E7%9F%A5a%26%23178%3B-2ab%3D5%2Cb%26%23178%3B%2B3ab%3D6%2C%E5%88%99a%26%23178%3B%2Bab%2Bb%26%23178%3B%3D%EF%BC%88%EF%BC%89%2Ca%26%23178%3B-5ab-b%26%23178%3B%3D%EF%BC%88%EF%BC%89)
已知a²-2ab=5,b²+3ab=6,则a²+ab+b²=(),a²-5ab-b²=()
已知a²-2ab=5,b²+3ab=6,则a²+ab+b²=(),a²-5ab-b²=()
已知a²-2ab=5,b²+3ab=6,则a²+ab+b²=(),a²-5ab-b²=()
两式相加得
a^2+ab+b^2=11
两式相减,得
a^2-5ab-b^2=-1
则a²+ab+b²=(11),a²-5ab-b²=(-1)