已知函数f(x)=sin(wx+π/3) (w>0) 若f(π/6)=f(π/3),且f(x)在区间(π/6,π/3)内有最大值,无最小值,则w=
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![已知函数f(x)=sin(wx+π/3) (w>0) 若f(π/6)=f(π/3),且f(x)在区间(π/6,π/3)内有最大值,无最小值,则w=](/uploads/image/z/4321117-37-7.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3Dsin%28wx%2B%CF%80%2F3%29+%28w%3E0%29+%E8%8B%A5f%28%CF%80%2F6%29%3Df%28%CF%80%2F3%29%2C%E4%B8%94f%28x%29%E5%9C%A8%E5%8C%BA%E9%97%B4%28%CF%80%2F6%2C%CF%80%2F3%29%E5%86%85%E6%9C%89%E6%9C%80%E5%A4%A7%E5%80%BC%2C%E6%97%A0%E6%9C%80%E5%B0%8F%E5%80%BC%2C%E5%88%99w%3D)
已知函数f(x)=sin(wx+π/3) (w>0) 若f(π/6)=f(π/3),且f(x)在区间(π/6,π/3)内有最大值,无最小值,则w=
已知函数f(x)=sin(wx+π/3) (w>0) 若f(π/6)=f(π/3),且f(x)在区间(π/6,π/3)内有最大值,无最小值,则w=
已知函数f(x)=sin(wx+π/3) (w>0) 若f(π/6)=f(π/3),且f(x)在区间(π/6,π/3)内有最大值,无最小值,则w=
f(π/6)=f(π/3),说明函数图像关于直线x=(π/6+π/3)/2(即x=π/4)对称.
f(x)在区间(π/6,π/3)内有最大值,无最小值,所以x=π/4时取到最大值.
且知函数周期大于π/3-π/6=π/6.
x=π/4时取到最大值,则wπ/4+π/3=2kπ+π/2,w=8k+2/3.k∈Z.
又周期为2π/w>π/6,0
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