方程2sin(2x+派/3)-1=0的解
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方程2sin(2x+派/3)-1=0的解
方程2sin(2x+派/3)-1=0的解
方程2sin(2x+派/3)-1=0的解
sin(2x+π/3)=1/2
2x+π/3=2kπ+π/6,或2x+π/3=2kπ+5π/6 (k∈Z)
x=kπ-π/12,或x=kπ+π/4 (k∈Z)
解三角涵数,首先要注意周期多解问题,相题中,变型即,sin(2x+派/3)=1/2,即, 2x+派/3=2k派+派/6 或 =2k派+5派/6