﹙3x²y³-x³y²+2分之1x²y²﹚÷﹙-2分之1xy﹚²
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 19:43:17
![﹙3x²y³-x³y²+2分之1x²y²﹚÷﹙-2分之1xy﹚²](/uploads/image/z/3818685-21-5.jpg?t=%EF%B9%993x%26%23178%3By%26%23179%3B-x%26%23179%3By%26%23178%3B%2B2%E5%88%86%E4%B9%8B1x%26%23178%3By%26%23178%3B%EF%B9%9A%C3%B7%EF%B9%99-2%E5%88%86%E4%B9%8B1xy%EF%B9%9A%26%23178%3B)
﹙3x²y³-x³y²+2分之1x²y²﹚÷﹙-2分之1xy﹚²
﹙3x²y³-x³y²+2分之1x²y²﹚÷﹙-2分之1xy﹚²
﹙3x²y³-x³y²+2分之1x²y²﹚÷﹙-2分之1xy﹚²
﹙3x²y³-x³y²+½x²y²﹚÷﹙-½xy﹚²=x²y²(3y-x+½)÷¼x²y²
=(3y-x+½)÷¼=12y-4x+2
条件呢
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来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 19:43:17
﹙3x²y³-x³y²+2分之1x²y²﹚÷﹙-2分之1xy﹚²
﹙3x²y³-x³y²+2分之1x²y²﹚÷﹙-2分之1xy﹚²
﹙3x²y³-x³y²+2分之1x²y²﹚÷﹙-2分之1xy﹚²
﹙3x²y³-x³y²+½x²y²﹚÷﹙-½xy﹚²=x²y²(3y-x+½)÷¼x²y²
=(3y-x+½)÷¼=12y-4x+2
条件呢