解方程:150²-x²=130²-(140-x)²
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 10:37:55
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解方程:150²-x²=130²-(140-x)²
解方程:150²-x²=130²-(140-x)²
解方程:150²-x²=130²-(140-x)²
答案:90
150²-x²=130²-(140-x)²
150²-130²=x²-(140-x)²
20*280=(2x-140)*140
5600/140=2x-140
x=90
150²-x²=130²-(140-x)²
(150+130)(130-150)=x ²-x²-280x+140²
280x=140×140+280×20
x=70+20
x=90
150²-x²=130²-(140-x)²
150²-x²=130²-140²+280x-x²
280x=150²+140²-130²
280x=25200
x=25200÷280
x=90
150²-x²=130²-(140-x)²
150²-130²=x²-(140-x)²
(150-130)(150+130) = (x-140+x)(x+140-x)
280*20=140(2x-140)
2x-140=2*20
x-70=20
x=90