5x²-4xy+y²-2x+1=0,求(x-y)2010
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/05 00:07:25
![5x²-4xy+y²-2x+1=0,求(x-y)2010](/uploads/image/z/3754006-70-6.jpg?t=5x%26%23178%3B-4xy%2By%26%23178%3B-2x%2B1%3D0%2C%E6%B1%82%28x-y%292010)
5x²-4xy+y²-2x+1=0,求(x-y)2010
5x²-4xy+y²-2x+1=0,求(x-y)2010
5x²-4xy+y²-2x+1=0,求(x-y)2010
5x^2-4xy+y^2-2x+1=0
(4x^2-4xy+y^2)+(x^2-2x+1)=0
(2x-y)^2+(x-1)^2=0
2x-y=0,x-1=0
x=1,y=2.
(x-y)^2010=(1-2)^2010=1