用因式分解法解下列方程:X²-3X-4=0 (2X-1)(X-1)=3
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 08:07:51
![用因式分解法解下列方程:X²-3X-4=0 (2X-1)(X-1)=3](/uploads/image/z/37494-54-4.jpg?t=%E7%94%A8%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E6%B3%95%E8%A7%A3%E4%B8%8B%E5%88%97%E6%96%B9%E7%A8%8B%EF%BC%9AX%26%23178%3B-3X-4%3D0+%EF%BC%882X-1%29%28X-1%29%3D3)
用因式分解法解下列方程:X²-3X-4=0 (2X-1)(X-1)=3
用因式分解法解下列方程:X²-3X-4=0 (2X-1)(X-1)=3
用因式分解法解下列方程:X²-3X-4=0 (2X-1)(X-1)=3
X²-3X-4=0
(x-4)(x+1)=0
x-4=0 x=4
x+1=0 x=-1
(2X-1)(X-1)=3
2x^2-3x+1=3
2x^2-3x-2=0
(2x+1)(x-2)=0
2x+1=0 x=-1/2
x-2=0 x=2
X²-3X-4=0
(x-4)(x+1)=0
x-4=0 x=4
x+1=0 x=-1
(2X-1)(X-1)=3
2x^2-3x+1=3
2x^2-3x-2=0
(2x+1)(x-2)=0
2x+1=0 x=-1/2
x-2=0 x=2
X²-3X-4=0
(x-4)(x+1)=0
x-4=0 x=4
x+1=0 x=-1