若方程4x²+(a²-3a-10)x+4a=0的两根互为相反数,则a=?
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![若方程4x²+(a²-3a-10)x+4a=0的两根互为相反数,则a=?](/uploads/image/z/3746948-68-8.jpg?t=%E8%8B%A5%E6%96%B9%E7%A8%8B4x%26%23178%3B%2B%28a%26%23178%3B-3a-10%29x%2B4a%3D0%E7%9A%84%E4%B8%A4%E6%A0%B9%E4%BA%92%E4%B8%BA%E7%9B%B8%E5%8F%8D%E6%95%B0%2C%E5%88%99a%3D%3F)
若方程4x²+(a²-3a-10)x+4a=0的两根互为相反数,则a=?
若方程4x²+(a²-3a-10)x+4a=0的两根互为相反数,则a=?
若方程4x²+(a²-3a-10)x+4a=0的两根互为相反数,则a=?
有a²-3a-10=0
有俩根 a<0
a=-2
x1+x2=-(a²-3a-10)/8=0
x1*x2=a<0
a²-3a-10=(a-5)(a+2)=0
a=5 (a=-2 舍去)