2x^2+2xy+y^2-2x+1=0,求xy
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![2x^2+2xy+y^2-2x+1=0,求xy](/uploads/image/z/3703338-18-8.jpg?t=2x%5E2%2B2xy%2By%5E2-2x%2B1%3D0%2C%E6%B1%82xy)
2x^2+2xy+y^2-2x+1=0,求xy
2x^2+2xy+y^2-2x+1=0,求xy
2x^2+2xy+y^2-2x+1=0,求xy
2x^2+2xy+y^2-2x+1=0
所以x^2+2xy+y^2+x^2-2x+1=0
所以(x+y)^2+(x-1)^2=0
所以x+y=0,x-1=0
所以x=1,y=-1
所以xy=-1
2x^2+2xy+y^2-2x+1=0
=x^2+2xy+y^2+x^2-2x+1=0
=(x+y)^2+(x-1)^2=0
所以x=1,y=-1
xy=-1