1.{√(3/2)+√(2/3)-√75+4√(3/50)}除以√(4/5)乘以(-2√15)2.已知a=2,b=1/3,求√(12ab)除以{1/√(2a)+1/√(3b)}的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/03 04:31:02
![1.{√(3/2)+√(2/3)-√75+4√(3/50)}除以√(4/5)乘以(-2√15)2.已知a=2,b=1/3,求√(12ab)除以{1/√(2a)+1/√(3b)}的值](/uploads/image/z/3668777-17-7.jpg?t=1.%7B%E2%88%9A%283%2F2%29%2B%E2%88%9A%282%2F3%29-%E2%88%9A75%2B4%E2%88%9A%283%2F50%29%7D%E9%99%A4%E4%BB%A5%E2%88%9A%EF%BC%884%2F5%EF%BC%89%E4%B9%98%E4%BB%A5%EF%BC%88-2%E2%88%9A15%EF%BC%892.%E5%B7%B2%E7%9F%A5a%3D2%2Cb%3D1%2F3%2C%E6%B1%82%E2%88%9A%EF%BC%8812ab%EF%BC%89%E9%99%A4%E4%BB%A5%EF%BD%9B1%2F%E2%88%9A%EF%BC%882a%EF%BC%89%2B1%2F%E2%88%9A%EF%BC%883b%EF%BC%89%7D%E7%9A%84%E5%80%BC)
1.{√(3/2)+√(2/3)-√75+4√(3/50)}除以√(4/5)乘以(-2√15)2.已知a=2,b=1/3,求√(12ab)除以{1/√(2a)+1/√(3b)}的值
1.{√(3/2)+√(2/3)-√75+4√(3/50)}除以√(4/5)乘以(-2√15)
2.已知a=2,b=1/3,求√(12ab)除以{1/√(2a)+1/√(3b)}的值
1.{√(3/2)+√(2/3)-√75+4√(3/50)}除以√(4/5)乘以(-2√15)2.已知a=2,b=1/3,求√(12ab)除以{1/√(2a)+1/√(3b)}的值
1.{√(3/2)+√(2/3)-√75+4√(3/50)}除以√(4/5)乘以(-2√15)
=[(√6)/2 +(√6)/3 - 5√3 + (2/5)√6]×√(5/4) ×(-2√15)
=[(5/6 + 2/5)*(√6)-5√3]×(-10√3)
=[(37/30)*(√6)-5√3]×(-10√3)
=-37√2 +150
2.已知a=2,b=1/3,求√(12ab)除以{1/√(2a)+1/√(3b)}的值
已知a=2,b=1/3,那么:
√(12ab)÷{1/√(2a)+1/√(3b)}
=√(12×2×1/3)÷{1/√(2×2)+1/√(3×1/3)}
=√8 ÷{1/2 +1}
=2√2 ÷ (3/2)
=2√2 × (2/3)
=4(√2)/3
原式=[√(6/4)+√(6/9)+√(25×3)+4×√(6/100)]×[-2×√(3×5)]÷√(20/25)=(1/2√6+1/3√6+5√3+2/5√6)×5√3=37/2√2+75
1. {√(3/2)+√(2/3)-√75+4√(3/50)}除以√(4/5)乘以(-2√15)
=[(√6)/2 +(√6)/3 - 5√3 + (2/5)√6]×√(5/4) ×(-2√15)
=[(5/6 + 2/5)*(√6)-5√3]×(-10√3)
=[(37/30)*(√6)-5√3]×(-10√3)
=-37√2 +150
2. 已...
全部展开
1. {√(3/2)+√(2/3)-√75+4√(3/50)}除以√(4/5)乘以(-2√15)
=[(√6)/2 +(√6)/3 - 5√3 + (2/5)√6]×√(5/4) ×(-2√15)
=[(5/6 + 2/5)*(√6)-5√3]×(-10√3)
=[(37/30)*(√6)-5√3]×(-10√3)
=-37√2 +150
2. 已知a=2,b=1/3,求√(12ab)除以{1/√(2a)+1/√(3b)}的值
已知a=2,b=1/3,那么:
√(12ab)÷{1/√(2a)+1/√(3b)}
=√8 ÷{1/2 +1}
=2√2 ÷ (3/2)
=2√2 × (2/3)
=4(√2)/3
收起