设集合a={a+2,a²,a²+3a+3},若1∈A,求a的值
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设集合a={a+2,a²,a²+3a+3},若1∈A,求a的值
设集合a={a+2,a²,a²+3a+3},若1∈A,求a的值
设集合a={a+2,a²,a²+3a+3},若1∈A,求a的值
答:
集合A={a+2,a²,a²+3a+3},若1∈A
则:
a+2=1或者a^2=1或者a^2+3a+3=1
所以:
a=-1或者a=1或者(a+2)(a+1)=0
所以:
a=-1或者a=1或者a=-2