化简求值:2x²y-[x²y+2(x²y-xy)]+y,其中x²=2x+1 y=2011/2012 我知道答案是0
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![化简求值:2x²y-[x²y+2(x²y-xy)]+y,其中x²=2x+1 y=2011/2012 我知道答案是0](/uploads/image/z/3169454-14-4.jpg?t=%E5%8C%96%E7%AE%80%E6%B1%82%E5%80%BC%EF%BC%9A2x%26%23178%3By-%5Bx%26%23178%3By%2B2%28x%26%23178%3By-xy%29%5D%2By%2C%E5%85%B6%E4%B8%ADx%26%23178%3B%3D2x%2B1+y%3D2011%2F2012+%E6%88%91%E7%9F%A5%E9%81%93%E7%AD%94%E6%A1%88%E6%98%AF0)
化简求值:2x²y-[x²y+2(x²y-xy)]+y,其中x²=2x+1 y=2011/2012 我知道答案是0
化简求值:2x²y-[x²y+2(x²y-xy)]+y,其中x²=2x+1 y=2011/2012 我知道答案是0
化简求值:2x²y-[x²y+2(x²y-xy)]+y,其中x²=2x+1 y=2011/2012 我知道答案是0
2x²y-[x²y+2(x²y-xy)]+y=2x²y-(3x²y-2xy)+y = -x²y+2xy+y= -(x²-2x-1)y 又因为 x²=2x+1 所以上式= -0y=0