已知数列{an}满足 a1=3,an+1=an+3n²+3n+2-1\n(n+1),求an的通项公式
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![已知数列{an}满足 a1=3,an+1=an+3n²+3n+2-1\n(n+1),求an的通项公式](/uploads/image/z/3155093-53-3.jpg?t=%E5%B7%B2%E7%9F%A5%E6%95%B0%E5%88%97%7Ban%7D%E6%BB%A1%E8%B6%B3+a1%3D3%2Can%2B1%3Dan%2B3n%26%23178%3B%2B3n%2B2-1%5Cn%28n%2B1%29%2C%E6%B1%82an%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F)
已知数列{an}满足 a1=3,an+1=an+3n²+3n+2-1\n(n+1),求an的通项公式
已知数列{an}满足 a1=3,an+1=an+3n²+3n+2-1\n(n+1),求an的通项公式
已知数列{an}满足 a1=3,an+1=an+3n²+3n+2-1\n(n+1),求an的通项公式
先上第一小题……
高中毕业好多年,实在是不知道公式怎么算了!
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