(2-3x)/(x-6)>1这个分式不等式是不是可以这样解?(2-3x)/(x-6)-1>0(2-3x)/(x-6)-(x-6)/(x-6)>0(-4x+8)/(x-6)>0然后分类讨论:-4x+8>0 -4x+80 x-6
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/01 23:04:15
![(2-3x)/(x-6)>1这个分式不等式是不是可以这样解?(2-3x)/(x-6)-1>0(2-3x)/(x-6)-(x-6)/(x-6)>0(-4x+8)/(x-6)>0然后分类讨论:-4x+8>0 -4x+80 x-6](/uploads/image/z/3010937-41-7.jpg?t=%282-3x%29%2F%28x-6%29%3E1%E8%BF%99%E4%B8%AA%E5%88%86%E5%BC%8F%E4%B8%8D%E7%AD%89%E5%BC%8F%E6%98%AF%E4%B8%8D%E6%98%AF%E5%8F%AF%E4%BB%A5%E8%BF%99%E6%A0%B7%E8%A7%A3%3F%EF%BC%882-3x%EF%BC%89%2F%EF%BC%88x-6%EF%BC%89-1%3E0%282-3x%29%2F%28x-6%29-%28x-6%29%2F%28x-6%29%3E0%28-4x%2B8%29%2F%28x-6%29%3E0%E7%84%B6%E5%90%8E%E5%88%86%E7%B1%BB%E8%AE%A8%E8%AE%BA%EF%BC%9A-4x%2B8%3E0+-4x%2B80+x-6)
(2-3x)/(x-6)>1这个分式不等式是不是可以这样解?(2-3x)/(x-6)-1>0(2-3x)/(x-6)-(x-6)/(x-6)>0(-4x+8)/(x-6)>0然后分类讨论:-4x+8>0 -4x+80 x-6
(2-3x)/(x-6)>1这个分式不等式是不是可以这样解?
(2-3x)/(x-6)-1>0
(2-3x)/(x-6)-(x-6)/(x-6)>0
(-4x+8)/(x-6)>0
然后分类讨论:
-4x+8>0 -4x+80 x-6
(2-3x)/(x-6)>1这个分式不等式是不是可以这样解?(2-3x)/(x-6)-1>0(2-3x)/(x-6)-(x-6)/(x-6)>0(-4x+8)/(x-6)>0然后分类讨论:-4x+8>0 -4x+80 x-6
正确答案!
可以啊,一般都是这么解的