f(x)=cos^2x-sin^2x,则f(2005TT/12)=?我的数学很烂,是在班里倒数的那些.f(x)是以5为周期的奇函数,且f(-3)=1,tana=2,f(20sinacosa)=?2005TT/12=2005 派/12
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![f(x)=cos^2x-sin^2x,则f(2005TT/12)=?我的数学很烂,是在班里倒数的那些.f(x)是以5为周期的奇函数,且f(-3)=1,tana=2,f(20sinacosa)=?2005TT/12=2005 派/12](/uploads/image/z/2832902-62-2.jpg?t=f%28x%29%3Dcos%5E2x-sin%5E2x%2C%E5%88%99f%282005TT%2F12%29%3D%3F%E6%88%91%E7%9A%84%E6%95%B0%E5%AD%A6%E5%BE%88%E7%83%82%2C%E6%98%AF%E5%9C%A8%E7%8F%AD%E9%87%8C%E5%80%92%E6%95%B0%E7%9A%84%E9%82%A3%E4%BA%9B.f%28x%29%E6%98%AF%E4%BB%A55%E4%B8%BA%E5%91%A8%E6%9C%9F%E7%9A%84%E5%A5%87%E5%87%BD%E6%95%B0%2C%E4%B8%94f%28-3%29%3D1%2Ctana%3D2%2Cf%2820sinacosa%29%3D%3F2005TT%2F12%3D2005+%E6%B4%BE%2F12)
f(x)=cos^2x-sin^2x,则f(2005TT/12)=?我的数学很烂,是在班里倒数的那些.f(x)是以5为周期的奇函数,且f(-3)=1,tana=2,f(20sinacosa)=?2005TT/12=2005 派/12
f(x)=cos^2x-sin^2x,则f(2005TT/12)=?
我的数学很烂,是在班里倒数的那些.
f(x)是以5为周期的奇函数,且f(-3)=1,tana=2,f(20sinacosa)=?
2005TT/12=2005 派/12
f(x)=cos^2x-sin^2x,则f(2005TT/12)=?我的数学很烂,是在班里倒数的那些.f(x)是以5为周期的奇函数,且f(-3)=1,tana=2,f(20sinacosa)=?2005TT/12=2005 派/12
f(x)=cos^2x-sin^2x=cos2x
f(2005π/12)
=cos2005π/6
=cos(-π/6)
=√3/2
----------------------------
tana=2
=>sina=2/√5;cosa=1/√5
=>sinacosa=2/5
=>f(20sinacosa)=f(8)=f(3)=-f(-3)=-1
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