a b 均为有理数 且满足 5-√2*a=2b+3/2√2-5 求 a b
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/27 21:07:59
![a b 均为有理数 且满足 5-√2*a=2b+3/2√2-5 求 a b](/uploads/image/z/2803975-7-5.jpg?t=a+b+%E5%9D%87%E4%B8%BA%E6%9C%89%E7%90%86%E6%95%B0+%E4%B8%94%E6%BB%A1%E8%B6%B3+5-%E2%88%9A2%2Aa%3D2b%2B3%2F2%E2%88%9A2-5+%E6%B1%82+a+b)
a b 均为有理数 且满足 5-√2*a=2b+3/2√2-5 求 a b
a b 均为有理数 且满足 5-√2*a=2b+3/2√2-5 求 a b
a b 均为有理数 且满足 5-√2*a=2b+3/2√2-5 求 a b
5-√2*a=2b+3/2√2-5
-√2*a-2b=+3/2√2-5-5
-√2*a-2b=3/2√2-10
√2*a+2b=10-3/2√2
a=-3/2,2b=10
a=-3/2,b=5
a=-3/2
b=5
5-√2*a=2b+3/2√2-5
-√2*a-2b=+3/2√2-5-5
-√2*a-2b=3/2√2-10
√2*a+2b=10-3/2√2
a=-3/2,2b=10
a=-3/2,b=5