解方程:3/(x-1)-(x+2)/(x∧2-x)=0是[3/(x-1)]-[(x+2)/(x∧2-x)]=0
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/02 13:02:30
![解方程:3/(x-1)-(x+2)/(x∧2-x)=0是[3/(x-1)]-[(x+2)/(x∧2-x)]=0](/uploads/image/z/251128-64-8.jpg?t=%E8%A7%A3%E6%96%B9%E7%A8%8B%3A3%2F%28x-1%29-%28x%2B2%29%2F%28x%E2%88%A72-x%29%3D0%E6%98%AF%5B3%2F%28x-1%29%5D-%5B%28x%2B2%29%2F%28x%E2%88%A72-x%29%5D%3D0)
解方程:3/(x-1)-(x+2)/(x∧2-x)=0是[3/(x-1)]-[(x+2)/(x∧2-x)]=0
解方程:3/(x-1)-(x+2)/(x∧2-x)=0
是[3/(x-1)]-[(x+2)/(x∧2-x)]=0
解方程:3/(x-1)-(x+2)/(x∧2-x)=0是[3/(x-1)]-[(x+2)/(x∧2-x)]=0
3/(x-1)-(x+2)/x(x-1)=0
两边乘x(x-1)
3x-(x+2)=0
3x-x-2=0
x=1
经检验,x=1时分母x-1=0
是增根,舍去
所以方程无解