1+cos2x+√3/2*(sinxcosx)化简具体步骤
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![1+cos2x+√3/2*(sinxcosx)化简具体步骤](/uploads/image/z/2483126-62-6.jpg?t=1%2Bcos2x%2B%E2%88%9A3%2F2%2A%28sinxcosx%29%E5%8C%96%E7%AE%80%E5%85%B7%E4%BD%93%E6%AD%A5%E9%AA%A4)
1+cos2x+√3/2*(sinxcosx)化简具体步骤
1+cos2x+√3/2*(sinxcosx)化简具体步骤
1+cos2x+√3/2*(sinxcosx)化简具体步骤
解1+cos2x+√3/2*(sinxcosx)
=1+2cos^2x-1+√3/2*(sinxcosx)
=2cos^2x+√3/2*sinxcosx
=cosx(2cosx+√3/2sinx)
=cosx×√19/2(4/√2cosx+√3/√19sinx)
=√19/2cosxcos(x-θ)(cosθ=4/√2,sinθ=√3/√19)