先化简 再求值 (9-a²)/(a²+6a+9)÷(a²-3a)/(a+3)+(3/a) 其中a=根号2
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![先化简 再求值 (9-a²)/(a²+6a+9)÷(a²-3a)/(a+3)+(3/a) 其中a=根号2](/uploads/image/z/241205-5-5.jpg?t=%E5%85%88%E5%8C%96%E7%AE%80+%E5%86%8D%E6%B1%82%E5%80%BC+%EF%BC%889-a%26%23178%3B%EF%BC%89%2F%EF%BC%88a%26%23178%3B%2B6a%2B9%29%C3%B7%EF%BC%88a%26%23178%3B-3a%EF%BC%89%2F%EF%BC%88a%2B3%EF%BC%89%2B%EF%BC%883%2Fa%EF%BC%89+%E5%85%B6%E4%B8%ADa%3D%E6%A0%B9%E5%8F%B72)
先化简 再求值 (9-a²)/(a²+6a+9)÷(a²-3a)/(a+3)+(3/a) 其中a=根号2
先化简 再求值 (9-a²)/(a²+6a+9)÷(a²-3a)/(a+3)+(3/a) 其中a=根号2
先化简 再求值 (9-a²)/(a²+6a+9)÷(a²-3a)/(a+3)+(3/a) 其中a=根号2
(9-a²)/(a²+6a+9)÷(a²-3a)/(a+3)+(3/a)
=-(a+3)(a-3)/(a+3)²×(a+3)/a(a-3)+(3/a)
=-1/a+3/a
=2/a
=2÷根号2
=根号2.
=(3+a)(3-a)/(a+3)²÷a(a-3)/(a+3)+(3/a)
=(3-a)/(a+3)×(a+3)/a(a-3)+(3/a)
=-1/a+(3/a)
=2/a
=根号2
九减a的平方化为九加三乘九减三
a的平方加六a加九化为(a加三)的平方
下面的大概就这样