数列不等式证明数列{an}中a1=2,a(n+1)=an/2 +1/an,求证:根号2
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![数列不等式证明数列{an}中a1=2,a(n+1)=an/2 +1/an,求证:根号2](/uploads/image/z/2117771-35-1.jpg?t=%E6%95%B0%E5%88%97%E4%B8%8D%E7%AD%89%E5%BC%8F%E8%AF%81%E6%98%8E%E6%95%B0%E5%88%97%7Ban%7D%E4%B8%ADa1%3D2%2Ca%EF%BC%88n%2B1%EF%BC%89%3Dan%2F2+%2B1%2Fan%2C%E6%B1%82%E8%AF%81%EF%BC%9A%E6%A0%B9%E5%8F%B72)
数列不等式证明数列{an}中a1=2,a(n+1)=an/2 +1/an,求证:根号2 数列不等式证明数列{an}中a1=2,a(n+1)=an/2 +1/an,求证:根号2
数列不等式证明
数列{an}中a1=2,a(n+1)=an/2 +1/an,求证:根号2
n=1,a1=2,成立
n=k,√2√2,所以取大于号.
a(k+1))=ak/2+1/ak