(3x-1)²=4(x+1)²
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![(3x-1)²=4(x+1)²](/uploads/image/z/2104180-52-0.jpg?t=%283x-1%29%26%23178%3B%3D4%28x%2B1%29%26%23178%3B)
(3x-1)²=4(x+1)²
(3x-1)²=4(x+1)²
(3x-1)²=4(x+1)²
(3x-1)²=4(x+1)²
→[(3x-1)+2(x+1)][(3x-1)-2(x+1)]=0
→(5x+1)(x-3)=0,
∴x1=-1/5, x2=3.
3x-1=2x+2或3x-1=-2x-2
X=3或-1/5
3X-1=2(X+1)或 -(3X-1)=2(X+1)
X=3或X=-1/5