设m,n是方程x²-(k-2)x+k²+3k+5=0的两个实数根,则m²+n²的最大值为
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![设m,n是方程x²-(k-2)x+k²+3k+5=0的两个实数根,则m²+n²的最大值为](/uploads/image/z/2086275-3-5.jpg?t=%E8%AE%BEm%2Cn%E6%98%AF%E6%96%B9%E7%A8%8Bx%26%23178%3B-%28k-2%29x%2Bk%26%23178%3B%2B3k%2B5%3D0%E7%9A%84%E4%B8%A4%E4%B8%AA%E5%AE%9E%E6%95%B0%E6%A0%B9%2C%E5%88%99m%26%23178%3B%2Bn%26%23178%3B%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E4%B8%BA)
设m,n是方程x²-(k-2)x+k²+3k+5=0的两个实数根,则m²+n²的最大值为
设m,n是方程x²-(k-2)x+k²+3k+5=0的两个实数根,则m²+n²的最大值为
设m,n是方程x²-(k-2)x+k²+3k+5=0的两个实数根,则m²+n²的最大值为
有实根,则delta=(k-2)^2-4(k^2+3k+5)=-3k^2-16k-16=-(3k+4)(k+4)>=0,得:-4=