已知(a+2)2+| b+1 | =0,求代数式5ab²—{2a²b—【3a²b—(4ab²—2a²b)】}的值
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![已知(a+2)2+| b+1 | =0,求代数式5ab²—{2a²b—【3a²b—(4ab²—2a²b)】}的值](/uploads/image/z/1998281-65-1.jpg?t=%E5%B7%B2%E7%9F%A5%EF%BC%88a%2B2%EF%BC%892%2B%7C+b%2B1+%7C+%3D0%2C%E6%B1%82%E4%BB%A3%E6%95%B0%E5%BC%8F5ab%26%23178%3B%E2%80%94%7B2a%26%23178%3Bb%E2%80%94%E3%80%903a%26%23178%3Bb%E2%80%94%284ab%26%23178%3B%E2%80%942a%26%23178%3Bb%EF%BC%89%E3%80%91%7D%E7%9A%84%E5%80%BC)
已知(a+2)2+| b+1 | =0,求代数式5ab²—{2a²b—【3a²b—(4ab²—2a²b)】}的值
已知(a+2)2+| b+1 | =0,求代数式5ab²—{2a²b—【3a²b—(4ab²—2a²b)】}的值
已知(a+2)2+| b+1 | =0,求代数式5ab²—{2a²b—【3a²b—(4ab²—2a²b)】}的值
根据题意得
a+2=0
b+1=0
∴a=-2
b=-1
5ab²—{2a²b—【3a²b—(4ab²—2a²b)】}
=5ab²—2a²b+3a²b—4ab²+2a²b
=ab²+3a²b
当a=-2,b=-1时
原式=-2-12=-14