求值(log4(3)+log8(3))×(log3(2)+log9(2))除了用应用换底公式换成以10为底的方法外,请问还能换成以谁为底更简便一些呢?
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![求值(log4(3)+log8(3))×(log3(2)+log9(2))除了用应用换底公式换成以10为底的方法外,请问还能换成以谁为底更简便一些呢?](/uploads/image/z/1995774-6-4.jpg?t=%E6%B1%82%E5%80%BC%28log4%283%29%2Blog8%283%29%29%C3%97%28log3%282%29%2Blog9%282%29%29%E9%99%A4%E4%BA%86%E7%94%A8%E5%BA%94%E7%94%A8%E6%8D%A2%E5%BA%95%E5%85%AC%E5%BC%8F%E6%8D%A2%E6%88%90%E4%BB%A510%E4%B8%BA%E5%BA%95%E7%9A%84%E6%96%B9%E6%B3%95%E5%A4%96%2C%E8%AF%B7%E9%97%AE%E8%BF%98%E8%83%BD%E6%8D%A2%E6%88%90%E4%BB%A5%E8%B0%81%E4%B8%BA%E5%BA%95%E6%9B%B4%E7%AE%80%E4%BE%BF%E4%B8%80%E4%BA%9B%E5%91%A2%3F)
求值(log4(3)+log8(3))×(log3(2)+log9(2))除了用应用换底公式换成以10为底的方法外,请问还能换成以谁为底更简便一些呢?
求值(log4(3)+log8(3))×(log3(2)+log9(2))
除了用应用换底公式换成以10为底的方法外,请问还能换成以谁为底更简便一些呢?
求值(log4(3)+log8(3))×(log3(2)+log9(2))除了用应用换底公式换成以10为底的方法外,请问还能换成以谁为底更简便一些呢?
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