(1) 求函数y=-tan(x+π/6)+2的定义域; (2)求函数y=tan(2x+π/3),x≠5π/12+kπ/2(k∈z)的周期
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![(1) 求函数y=-tan(x+π/6)+2的定义域; (2)求函数y=tan(2x+π/3),x≠5π/12+kπ/2(k∈z)的周期](/uploads/image/z/1995242-50-2.jpg?t=%281%29+%E6%B1%82%E5%87%BD%E6%95%B0y%3D-tan%28x%2B%CF%80%2F6%29%2B2%E7%9A%84%E5%AE%9A%E4%B9%89%E5%9F%9F%3B+%282%29%E6%B1%82%E5%87%BD%E6%95%B0y%3Dtan%282x%2B%CF%80%2F3%29%2Cx%E2%89%A05%CF%80%2F12%2Bk%CF%80%2F2%28k%E2%88%88z%29%E7%9A%84%E5%91%A8%E6%9C%9F)
(1) 求函数y=-tan(x+π/6)+2的定义域; (2)求函数y=tan(2x+π/3),x≠5π/12+kπ/2(k∈z)的周期
(1) 求函数y=-tan(x+π/6)+2的定义域; (2)求函数y=tan(2x+π/3),x≠5π/12+kπ/2(k∈z)的周期
(1) 求函数y=-tan(x+π/6)+2的定义域; (2)求函数y=tan(2x+π/3),x≠5π/12+kπ/2(k∈z)的周期
(1)由f(x)=tanx是奇函数 -tanx=tan(-x) y=-tan(x+π/6)+2=tan(-x-π/6)+2 令z=-x-π/6 y=tanz+2的定义域为(-π/2+2kπ,π/2+2kπ) k∈z -π/2+2kπ<-x-π/6<π/2+2kπ -2π/3+2kπ