已知X2-5X-14=0求(x-1)×(2x-1)-(x+1)2+1
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![已知X2-5X-14=0求(x-1)×(2x-1)-(x+1)2+1](/uploads/image/z/1989319-31-9.jpg?t=%E5%B7%B2%E7%9F%A5X2-5X-14%3D0%E6%B1%82%28x-1%29%C3%97%282x-1%29-%28x%2B1%292%2B1)
已知X2-5X-14=0求(x-1)×(2x-1)-(x+1)2+1
已知X2-5X-14=0求(x-1)×(2x-1)-(x+1)2+1
已知X2-5X-14=0求(x-1)×(2x-1)-(x+1)2+1
X2-5X-14=0
X2-5X=14
(x-1)×(2x-1)-(x+1)2+1
=2x^2-2x-x+1-x^2-2x-1+1
=x^2-5x+1
=14+1
=15
...不知道
首先拿十子字相乘法求出x2-5x-14=0 再待入得x1=18 x2=54 你再算一下 我算的快 不一定对