已知|a+1|+(a-b-2)²=0化简ab-[3a²b(4ab²+ab)-3a²b],并求出它的值急
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 02:11:36
![已知|a+1|+(a-b-2)²=0化简ab-[3a²b(4ab²+ab)-3a²b],并求出它的值急](/uploads/image/z/1978695-63-5.jpg?t=%E5%B7%B2%E7%9F%A5%7Ca%2B1%7C%2B%28a-b-2%29%26%23178%3B%EF%BC%9D0%E5%8C%96%E7%AE%80ab-%5B3a%26%23178%3Bb%EF%BC%884ab%26%23178%3B%2Bab%EF%BC%89-3a%26%23178%3Bb%5D%2C%E5%B9%B6%E6%B1%82%E5%87%BA%E5%AE%83%E7%9A%84%E5%80%BC%E6%80%A5)
已知|a+1|+(a-b-2)²=0化简ab-[3a²b(4ab²+ab)-3a²b],并求出它的值急
已知|a+1|+(a-b-2)²=0化简ab-[3a²b(4ab²+ab)-3a²b],并求出它的值
急
已知|a+1|+(a-b-2)²=0化简ab-[3a²b(4ab²+ab)-3a²b],并求出它的值急
|a+1|+(a-b-2)²=0,则a+1=0,a-b-2=0,则a=-1,b=-3
ab-[3a²b+(4ab²+ab)-3a²b]
=-4ab²
=-4×(-1)×(-3)²
=36
a=1或-1,a-b=2
a=1.b=1代入得-11
a=-1b=-3代入-303
已知|a+1|+(a-b-2)²=0,因为绝对值和平方都为非负数,所以a+1=0,a-b-2=0,a=-1,b=-3
ab-[3a²b+(4ab²+ab)-3a²b]
ab-3a²b-4ab²-ab+3a²b
=-4ab²
=-4×(-1)×(-3)²
=36