x²+3x(3x)²/(2x)²+2x²怎么算?
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x²+3x(3x)²/(2x)²+2x²怎么算?
x²+3x(3x)²/(2x)²+2x²怎么算?
x²+3x(3x)²/(2x)²+2x²怎么算?
x²+3x(3x)²/(2x)²+2x²
=x²+27x²/4x²+2x²
=28x²/6x²
=14/3
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[x²+3(3x)²]/[(2x)²+2x²]
=(x²+3×9x²)/(4x²+2x²)
=(x²+27x²)/6x²
=28x²/6x²
=14/3