已知x²-5x-2013=0,则代数式x-2分之(x-2)²-(x-1)²+1 的值为 -----化简: a²+6a+9分之9-a² ÷ a+3分之a²-3a+ a分之1
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 02:12:20
![已知x²-5x-2013=0,则代数式x-2分之(x-2)²-(x-1)²+1 的值为 -----化简: a²+6a+9分之9-a² ÷ a+3分之a²-3a+ a分之1](/uploads/image/z/1835798-14-8.jpg?t=%E5%B7%B2%E7%9F%A5x%26%23178%3B-5x-2013%3D0%2C%E5%88%99%E4%BB%A3%E6%95%B0%E5%BC%8Fx-2%E5%88%86%E4%B9%8B%EF%BC%88x-2%EF%BC%89%26%23178%3B-%EF%BC%88x-1%EF%BC%89%26%23178%3B%2B1+%E7%9A%84%E5%80%BC%E4%B8%BA+-----%E5%8C%96%E7%AE%80%EF%BC%9A+a%26%23178%3B%2B6a%2B9%E5%88%86%E4%B9%8B9-a%26%23178%3B+%C3%B7+a%2B3%E5%88%86%E4%B9%8Ba%26%23178%3B-3a%2B+a%E5%88%86%E4%B9%8B1)
已知x²-5x-2013=0,则代数式x-2分之(x-2)²-(x-1)²+1 的值为 -----化简: a²+6a+9分之9-a² ÷ a+3分之a²-3a+ a分之1
已知x²-5x-2013=0,则代数式x-2分之(x-2)²-(x-1)²+1 的值为 -----
化简: a²+6a+9分之9-a² ÷ a+3分之a²-3a+ a分之1
已知x²-5x-2013=0,则代数式x-2分之(x-2)²-(x-1)²+1 的值为 -----化简: a²+6a+9分之9-a² ÷ a+3分之a²-3a+ a分之1
∵x²-5x-2013=0
∴x²-5x=2013
[(x-2)²-(x-1)²+1]/(x-2)
=[x²-4x+4-x²+2x-1+1]/(x-2)
=(-2x+4)/(x-2)
=-2(x-2)/(x-2)
=-2
a²+6a+9分之9-a² ÷ a+3分之a²-3a+ a分之1
=(3-a)/(3+a)*(a+3)/(a-3)a+1/a
=[(3+a)²+1]/a