先化简再求值(ab分子a²+b²+2)÷a-b分之a²-b²
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/05 05:40:58
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先化简再求值(ab分子a²+b²+2)÷a-b分之a²-b²
先化简再求值(ab分子a²+b²+2)÷a-b分之a²-b²
先化简再求值(ab分子a²+b²+2)÷a-b分之a²-b²
(ab分子a²+b²+2)÷a-b分之a²-b²
=(a²+b²+2ab)/ab÷[(a+b)(a-b)/(a-b)]
=(a+b)²/ab÷(a+b)
=(a+b)/ab
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