已知函数f(x)=cos²[(π/4)+ x] - cos²[(π/4)- x].则f(π/12)等于( )
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![已知函数f(x)=cos²[(π/4)+ x] - cos²[(π/4)- x].则f(π/12)等于( )](/uploads/image/z/1730779-43-9.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3Dcos%26%23178%3B%5B%EF%BC%88%CF%80%2F4%EF%BC%89%2B+x%5D+-+cos%26%23178%3B%5B%EF%BC%88%CF%80%2F4%EF%BC%89-+x%5D.%E5%88%99f%EF%BC%88%CF%80%2F12%EF%BC%89%E7%AD%89%E4%BA%8E%EF%BC%88+%EF%BC%89)
已知函数f(x)=cos²[(π/4)+ x] - cos²[(π/4)- x].则f(π/12)等于( )
已知函数f(x)=cos²[(π/4)+ x] - cos²[(π/4)- x].则f(π/12)等于( )
已知函数f(x)=cos²[(π/4)+ x] - cos²[(π/4)- x].则f(π/12)等于( )
将x换成那个数,计算得-1/2