设f(x)在区间[a,b]上连续,则∫f(x)dx-∫f(t)dt(区间都是[a,b])的值为?
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![设f(x)在区间[a,b]上连续,则∫f(x)dx-∫f(t)dt(区间都是[a,b])的值为?](/uploads/image/z/1730767-31-7.jpg?t=%E8%AE%BEf%28x%29%E5%9C%A8%E5%8C%BA%E9%97%B4%5Ba%2Cb%5D%E4%B8%8A%E8%BF%9E%E7%BB%AD%2C%E5%88%99%E2%88%ABf%28x%29dx%EF%BC%8D%E2%88%ABf%28t%29dt%EF%BC%88%E5%8C%BA%E9%97%B4%E9%83%BD%E6%98%AF%5Ba%2Cb%5D%EF%BC%89%E7%9A%84%E5%80%BC%E4%B8%BA%3F)
设f(x)在区间[a,b]上连续,则∫f(x)dx-∫f(t)dt(区间都是[a,b])的值为?
设f(x)在区间[a,b]上连续,则∫f(x)dx-∫f(t)dt(区间都是[a,b])的值为?
设f(x)在区间[a,b]上连续,则∫f(x)dx-∫f(t)dt(区间都是[a,b])的值为?
因为∫f(x)dx=∫f(t)dt(积分值与变量无关)
所以∫f(x)dx-∫f(t)dt=0