若x-1的绝对值+(y+3)²+根号x+y+z=0,求x,y,z的值.要过程!!!
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![若x-1的绝对值+(y+3)²+根号x+y+z=0,求x,y,z的值.要过程!!!](/uploads/image/z/1658751-15-1.jpg?t=%E8%8B%A5x-1%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%2B%EF%BC%88y%2B3%EF%BC%89%26%23178%3B%2B%E6%A0%B9%E5%8F%B7x%2By%2Bz%3D0%2C%E6%B1%82x%2Cy%2Cz%E7%9A%84%E5%80%BC.%E8%A6%81%E8%BF%87%E7%A8%8B%EF%BC%81%EF%BC%81%EF%BC%81)
若x-1的绝对值+(y+3)²+根号x+y+z=0,求x,y,z的值.要过程!!!
若x-1的绝对值+(y+3)²+根号x+y+z=0,求x,y,z的值.
要过程!!!
若x-1的绝对值+(y+3)²+根号x+y+z=0,求x,y,z的值.要过程!!!
|x-1|=0,(y+3)²=0,x+y+z=0
所以x=1,y=-3,z=2
|x-1|=0,(y+3)²=0,x+y+z=0
所以x=1,y=-3,z=2
依题意可列方程组 x-1=0 y+3=0 3. x+y+z=0 解得 1.x=1 2.y=-3 3.z=2