已知x,y满足x(+1)-(x²+2y)=1,求x²+4xy+4y²-2x+4y的值.抱歉,是x(x+1)-(x²+2y)=1
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![已知x,y满足x(+1)-(x²+2y)=1,求x²+4xy+4y²-2x+4y的值.抱歉,是x(x+1)-(x²+2y)=1](/uploads/image/z/1614753-9-3.jpg?t=%E5%B7%B2%E7%9F%A5x%2Cy%E6%BB%A1%E8%B6%B3x%28%2B1%29-%28x%26%23178%3B%2B2y%29%3D1%2C%E6%B1%82x%26%23178%3B%2B4xy%2B4y%26%23178%3B-2x%2B4y%E7%9A%84%E5%80%BC.%E6%8A%B1%E6%AD%89%EF%BC%8C%E6%98%AFx%28x%2B1%29-%28x%26%23178%3B%2B2y%29%3D1)
已知x,y满足x(+1)-(x²+2y)=1,求x²+4xy+4y²-2x+4y的值.抱歉,是x(x+1)-(x²+2y)=1
已知x,y满足x(+1)-(x²+2y)=1,求x²+4xy+4y²-2x+4y的值.
抱歉,是x(x+1)-(x²+2y)=1
已知x,y满足x(+1)-(x²+2y)=1,求x²+4xy+4y²-2x+4y的值.抱歉,是x(x+1)-(x²+2y)=1
x(x+1)-(x^2+2y)=1 => x-2y=1
(x-2y-1)^2 = (x-2y)^2 -2(x-2y) +1 = x^2 -4xy + 4y^2 -2x+4y +1 =0
所以x^2 -4xy + 4y^2 -2x+4y =-1