cos7π/3-sin^2(17π/4)-1/3tan^2(π/3)sin3π/2+cos0=?
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/27 12:34:38
![cos7π/3-sin^2(17π/4)-1/3tan^2(π/3)sin3π/2+cos0=?](/uploads/image/z/1595892-12-2.jpg?t=cos7%CF%80%2F3-sin%5E2%2817%CF%80%2F4%29-1%2F3tan%5E2%28%CF%80%2F3%29sin3%CF%80%2F2%2Bcos0%3D%3F)
cos7π/3-sin^2(17π/4)-1/3tan^2(π/3)sin3π/2+cos0=?
cos7π/3-sin^2(17π/4)-1/3tan^2(π/3)sin3π/2+cos0=?
cos7π/3-sin^2(17π/4)-1/3tan^2(π/3)sin3π/2+cos0=?
cos(7π/3)-sin^2(17π/4)-1/3tan^2(π/3)sin(3π/2)+cos0
=cos(π/3)-sin^2(π/4)-1/3tan^2(π/3)sin(3π/2)+cos0
=1/2-(√2/2)^2-(1/3)*(√3)^2*(-1)+1
=1/2-1/2+1+1
=2
如果不懂,祝学习愉快!