若(x-1)(x^2+mx+n)=x^3-6x^2+11x-6,求m,n的值请有心人在22日晚上7:00之前给出答案,
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![若(x-1)(x^2+mx+n)=x^3-6x^2+11x-6,求m,n的值请有心人在22日晚上7:00之前给出答案,](/uploads/image/z/1563153-33-3.jpg?t=%E8%8B%A5%28x-1%29%28x%5E2%2Bmx%2Bn%29%3Dx%5E3-6x%5E2%2B11x-6%2C%E6%B1%82m%2Cn%E7%9A%84%E5%80%BC%E8%AF%B7%E6%9C%89%E5%BF%83%E4%BA%BA%E5%9C%A822%E6%97%A5%E6%99%9A%E4%B8%8A7%EF%BC%9A00%E4%B9%8B%E5%89%8D%E7%BB%99%E5%87%BA%E7%AD%94%E6%A1%88%2C)
若(x-1)(x^2+mx+n)=x^3-6x^2+11x-6,求m,n的值请有心人在22日晚上7:00之前给出答案,
若(x-1)(x^2+mx+n)=x^3-6x^2+11x-6,求m,n的值
请有心人在22日晚上7:00之前给出答案,
若(x-1)(x^2+mx+n)=x^3-6x^2+11x-6,求m,n的值请有心人在22日晚上7:00之前给出答案,
x^3-6x^2+11x-6
=x^3-x^2-5x^2+11x-6
=x^2*(x-1)-(5x^2-11x+6)
=x^2*(x-1)-(x-1)(5x-6)
=(x-1)(x^2-5x+6)
故:m=-5,n=6
(x-1)(x^2+mx+n)=x^3+mx^2+nx-x^2-mx-n=x^3+(m-1)x^2+(n-m)x-n
因为x^3-6x^2+11x-6=(x-1)(x^2+mx+n),
所以x^3+(m-1)x^2+(n-m)x-n=x^3-6x^2+11x-6
根据恒等式性质,得n=6,m=-5
好难啊
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